In a​ film, a character is criticized for marrying a woman when he is three times her age. He wittily​ replies, "Ah, but in 25years time I shall only be twiceher​ age." How old are the man and the​ woman?

Respuesta :

Answer:age of the man: 75 age of the woman:25

Step-by-step explanation:

First, We need to define the variables

x: age of the man

y: age of the woman

at the first time he has three times her age

x=3y                (1)

in 25 years time

(x+25)=2(y+25)                 (2)

we clear the equation

X+25=2y+50

X=2y+25

we substitute in the (1) equation:

2y+25=3y

y=25

x=3*25=75

Answer:

The woman its 25 years old. The man its 50.

Step-by-step explanation:

Let the age of the man (in years) be [tex]y_{man}[/tex] and the age of the woman (in years) be [tex]y_{woman}[/tex], right now he is three times her age, so:

[tex]y_{man} \ = \ 3 \ y_{woman}[/tex]

We also know that in 25 years, his age, [tex]y_{man25}[/tex], will be two times the age of hers, [tex]y_{woman25}[/tex], so:

[tex]y_{man25} \ = \ 2 \ y_{woman25}[/tex].

Now, of course, the age of each one, in 25 years, will be the same age they got right now plus 25 years;

[tex]y_{man25} \ = y_{man} + 25[/tex]

[tex]y_{woman25} \ = y_{woman} + 25[/tex]

We can replace this values on our second equation, and get:

[tex]y_{man} + 25 \ = \ 2 \ (y_{woman} + 25)[/tex]

Working it a little:

[tex]y_{man} \ = \ 2 \ y_{woman} + 2* 25 - 25[/tex]

[tex]y_{man} \ = \ 2 \ y_{woman} + 50 - 25[/tex]

[tex]y_{man} \ = \ 2 \ y_{woman} + 25[/tex]

We can replace this value on our first equation:

[tex]\ 2 \ y_{woman} + 25 \ = \ 3 \ y_{woman}[/tex]

[tex] 25 \ = \ 3 \ y_{woman} - \ 2 \ y_{woman} [/tex]

[tex] 25 \ = (\ 3 \ - \ 2\ ) y_{woman} [/tex]

[tex] 25 \ = y_{woman} [/tex]

The woman its 25 years old! We know the man its three times that age, so:

[tex] y_{man} = 3* 25 = 75 [/tex].

The man its 75 years old!

In 25 years she will be 50 and he will be 100, exactly two times her age. :)

Q&A Education