Answer:
i) [tex]=3x^2+19x+6[/tex]
ii) (f-g)(x)=2x-5
iii) (f+g)(-1)=3
Step-by-step explanation:
f(x)=3x+1
g(x)=x+6
we are asked to determine
i) (f.g)(x) = f(x).g(x)
[tex]=(3x+1)(x+6)[/tex]
[tex]=3xx+3x\cdot \:6+1\cdot \:x+1\cdot \:6[/tex]
[tex]=3xx+3\cdot \:6x+1\cdot \:x+1\cdot \:6[/tex]
[tex]=3x^2+19x+6[/tex]
ii) (f-g)(x)=f(x)-g(x)
=(3x+1)-(x+6)
=3x+1-x-6
(f-g)(x)=2x-5
iii) (f+g)(x) = f(x) + g(x)
= (3x+1)+(x+6)
= 3x+x+1+6
(f+g)(x)=4x+7
(f+g)(-1)=4(-1)+7
=-4+7
(f+g)(-1)=3
