Consider the following C program.#include int main(int argc, char argv[]){ char temp; strcpy(temp,argv[0]); return 0;}Why is the above code incorrect (i.e., likely to crash)?Write your explanation here:

Question

06-09-2019
Engineering

contestada

Consider the following C program.#include int main(int argc, char argv[]){ char temp; strcpy(temp,argv[0]); return 0;}Why is the above code incorrect (i.e., likely to crash)?Write your explanation here:

Respuesta :

Otras preguntas

Cause Effect What were the Causes?: Following the presidency of Thomas Jefferson, presidents James Madison and James Monroe helped establish the United States a

i can't figure this out, can someone help me?

In a race in which 6 automobiles are entered and there are no ties, in how many ways can the first three finishers come in?

Aerotron Electronics has just bought a used delivery truck for $15,000. The small business paid $1,000 down and financed the rest, with the agreement to pay not

1*9999999999999999999999999, i will give brainliest, but you mut have every single 9 in the answer, ok?

Subtract. 7/9−1/4 Enter your answer in simplest form

A two-sample t-test for a difference in means will be conducted to investigate mean gasoline prices in two states. From each state, 45 gasoline stations will be

A rectangular park is 5/6 miles wide and 1. 5/6 miles long what is the area of the park enter your anwer as a mixed number in simplest form

Jerry was trying out for the cross country team. He has to be able to run an 8.5 min mile. If he ran 5 mi in 45 mins last weekend, will this rate be good enough

Find the volume of the pyramid below. 5.6 ft : 6 ft 3 ft

klefenz klefenz · Answer 1 · 2019-09-11T19:48:00+02:00

Answer:

Pointer temp is never set.

Explanation:

To begin with the #include statement doesn't include anything, however that won't be a problem.

However temp is a pointer that is declared and then read from without having written anything to it.

Not only is the memory address it points to never written to, the address is never set and then attempted to read from. While this might compile, probably with warnings, the machine won't be able to execute it.

Consider the following C program.#include int main(int argc, char *argv[]){ char *temp; strcpy(temp,argv[0]); return 0;}Why is the above code incorrect (i.e., likely to crash)?Write your explanation here:

Respuesta :

Otras preguntas

Consider the following C program.#include int main(int argc, char argv[]){ char temp; strcpy(temp,argv[0]); return 0;}Why is the above code incorrect (i.e., likely to crash)?Write your explanation here: