Answer:
7.407 m
Explanation:
Let the west direction is positive so the east direction is taken as negative.
initial velocity, u = 6.5 m/s
Final velocity, v = 1.5 m/s
acceleration, a = - 2.7 m/s^2
Let it travels a distance s during this acceleration.
Use third equation of motion, we get
[tex]v^{2}=u^{2}+2as[/tex]
[tex]1.5^{2}=6.5^{2}-2\times2.7 \times s[/tex]
[tex]2.25=42.25-5.4s[/tex]
s = 7.407 m
Thus, the distance traveled is 7.407 m.
