Answer:
(a) A = 1 mm
(b) [tex]V_{max}=0.77872 m/s[/tex]
(c) [tex]a_{max}=606.4 m/s^{2}/tex]
Explanation:
Distance moved back and forth = 2 mm
Frequency, f = 124 Hz
So, amplitude is the half of the distance traveled back and forth.
(a) So, amplitude, A = 1 mm
(b) Angular frequency, ω = 2 π f = 2 x 3.14 x 124 = 778.72 rad/s
The formula for the maximum speed is given by
[tex]V_{max}=\omega \times A[/tex]
[tex]V_{max}=778.72 \times 0.001[/tex]
[tex]V_{max}=0.77872 m/s[/tex]
(c) The formula for the maximum acceleration is given by
[tex]a_{max}=\omega ^{2}A[/tex]
[tex]a_{max}=778.72 ^{2}\times 0.001[/tex]
[tex]a_{max}=606.4 m/s^{2}/tex]
