Answer:
The student who runs 3/4 mile in 6 minutes is faster than a student who runs 1/2 mile in 5 minutes, because his speed is greater
Step-by-step explanation:
we know that
The speed is equal to divide the distance by the time
Let
s ------> the speed
step 1
Find the speed of the student who runs 3/4 mile in 6 minutes
[tex]s=\frac{(3/4)}{6}= 0.125\frac{mi}{min}[/tex]
step 2
Find the speed of the student who runs 1/2 mile in 5 minutes
[tex]s=\frac{(1/2)}{5}= 0.10\frac{mi}{min}[/tex]
step 3
Compare the speed
[tex]0.125 > 0.10[/tex]
therefore
The student who runs 3/4 mile in 6 minutes is faster than a student who runs 1/2 mile in 5 minutes, because his speed is greater
