Find the distance between
-2-3i
and
3+9i
Answer:
13
Step-by-step explanation:
We can consider the complex number [tex]x+iy[/tex] as point with coordinates [tex](x,y),[/tex] where [tex]x[/tex] is real part of the complex number and [tex]y[/tex] is an imaginary part of the complex number.
The distance between two complex numbers is exactly tha distance between two points corresponding to each number.
[tex]z_1=-2-3i\Rightarrow A(-2,-3)\\ \\z_2=3+9i\Rightarrow B(3,9)[/tex]
Now find the distance between A and B:
[tex]AB=\sqrt{(-2-3)^2+(-3-9)^2}=\sqrt{(-5)^2+(-12)^2}=\sqrt{25+144}=\sqrt{169}=13\ units[/tex]