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Let P = (3, 2, −2) and Q = (7, 9, 9). Find the coordinates of the following. The point on the line through PQ whose distance from P is twice its distance from Q and which does not lie between these two points.

Respuesta :

Answer:

point A ON THE LINE PQ is ( 11,16,20)

Step-by-step explanation:

GIVEN DATA:

P (3,2, -2)

Q(7,9,9)

SUPPOSE point A has a cordintates (x,y,z)

given that AP = 2AQ

Q is midpoint of AP

So we have[tex]\frac{(x,y,z)+(3,2,-2)}{2} = (7,9,9)[/tex]

x+3 = 14.........1

y+2= 18..........2

z-2 =18...........3

x = 11 from equation 1

y = 16 from equation 2

z = 20 from equation 3

Therefore point A ON THE LINE PQ is ( 11,16,20)

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