Answer:
0.21108
Explanation:
Given,
Mean,
[tex]\mu = 110\text{ gram}[/tex]
Standard deviation,
[tex]\sigma = 25\text{ gram}[/tex]
Let X represents the amount of pyridoxine contained by vitamin,
So, the probability of vitamin will contain between 82 and 100 grams of pyridoxine,
= P( 82 ≤ X ≤ 100 )
[tex]P(\frac{82-\mu}{\sigma}\leq \frac{X-\mu}{\sigma}\leq \frac{100-\mu}{\sigma})[/tex]
[tex]P(\frac{82 - 110}{25}\leq z \leq \frac{100-110}{25})[/tex]
[tex]P(-1.12\leq z\leq -0.4)[/tex]
[tex]P(z\leq -0.4)-P(z\leq -1.12)[/tex]
[tex]=0.34458-0.13350[/tex]
= 0.21108
