A particular nucleus of the element plutonium contains 94 protons and 150 neutrons. What is the magnitude of the force from the nucleus on a single electron that is at a distance of 0.563 × 10–12 m from the plutonium nucleus?

Respuesta :

Answer:

6.83 × 10⁻² N

Explanation:

Given:

Number of protons contained by plutonium = 94

Number of neutrons contained by plutonium = 150

Total charge on nucleus, Q = Number of electrons × charge on an electron

or

Q = 94 × 1.6 × 10⁻¹⁹ C

Distance between the nucleus and the electron, r = 0.563 × 10⁻¹² m

Now,

the force is given as;

[tex]F=\frac{kQq}{r^2}[/tex]

where,

k is the Coulomb's constant = 9 × 10⁹ Nm²/C²

q is the charge on the electron

on substituting the respective values, we get

[tex]F=\frac{9\times10^9\times94\times1.6\times10^{-19}\times1.6\times10^{-19}}{(0.563\times10^{-12})^2}[/tex]

or

F = 6.83 × 10⁻² N

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