Answer:
[tex]C=-\dfrac{10}{17}(F-32)[/tex]
Explanation:
Given that
32° F corresponds to 0 °C. ---Point 1
212° F corresponds to 100 °C.----Point 2
We know that if two point is given that equation of line can be found as
[tex]y-y_1=\dfrac{y_2-y_1}{x_2-x_2}(x-x_1)[/tex]
Lets C in y- direction and F in x- direction,so we can say that
[tex]C-C_1=\dfrac{C_2-C_1}{F_2-F_2}(F-F_1)[/tex]
[tex]C-0=\dfrac{100-0}{32-212}(F-32)[/tex]
[tex]C=-\dfrac{10}{17}(F-32)[/tex]
So the linear relationship is
[tex]C=-\dfrac{10}{17}(F-32)[/tex]
