help me please! What is the equation of the line graphed below?
Answer:
y = - [tex]\frac{5}{2}[/tex] x - 2
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (0, - 2) and (x₂, y₂ ) = (- 2, 3) ← 2 points on the line
m = [tex]\frac{3+2}{-2-0}[/tex] = - [tex]\frac{5}{2}[/tex]
note the line crosses the y- axis at (0, - 2) ⇒ c = - 2
y = - [tex]\frac{5}{2}[/tex] x - 2 ← equation of line
Answer:
(0,-2) (-2, 3)
(3+2)/(-2-0)= -5/2
y + 2 = -5/2(x - 0)
y + 2 =( -5/2)x - 0
y = (-5/2)x - 2