Part A An unopened can of soda has an aqueous CO2 concentration of 0.21 M at 25.0 °C. What is the partial pressure of the gas in the can in torr? The Henry's law constant for CO2 at 25 °C is 3.4 × 10−2 mol/L-atm.

Respuesta :

Answer:

Partial pressure = 4689 torr

Explanation:

Given:

Concentration of CO2, c = 0.21 M= 0.21 mol/L

Henry's constant, k for CO2 = 3.4*10^-2 mol/L-atm

To determine:

the partial pressure, P

Calculation:

As per Henry's law, the concentration c of a gas is related to the pressure, p as follows:

[tex]C = k*p\\\\p = \frac{C}{k} = \frac{0.21 mol/L}{3.4*10^{-2}mol/L-atm} =6.17 atm[/tex]

Conversion from atm to torr

1 atm = 760 torr

[tex]p =6.17*760 = 4689 torr[/tex]

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