Michael is going to the store 6 miles away. He rides his bike at 12 mph for the first half of the trip, then walks at 4 mph for the remainder. Michael's average speed for the trip to the store is closest to:

Respuesta :

Answer:

6 mph

Explanation:

Total distance = 6 miles

Speed for the first half that means first 3 miles is 12 mph.

Speed for the next half that means next 3 miles is 4 mph.

Let t1 be the time taken to go for first half and then t2 be the time taken to go second half

By the use of formula for time.

time = distance / speed

[tex]t_{1}=\frac{3}{12}=\frac{1}{4}h[/tex]

[tex]t_{2}=\frac{3}{4}=\frac{3}{4}h[/tex]

total time taken in the 6 miles

[tex]t = t_{1}+t_{2}=\frac{1}{4}+\frac{3}{4}=1 h[/tex]

Average speed is defined as the ratio of total distance traveled to the total time taken.

So, Average speed in the entire journey is given by

[tex]V_{av}=\frac{6}{1}=6mph[/tex]

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