Assume that each of the 6 numbers has an equal probability of showing up for each die.
The probability of obtaining a six from the red die is 1/6, or
P(6 from the red die) = 1/6.
Similarly,
P(6 from the green die) = 1/6.
The tossing of the red die, followed by the tossing of the green die are independent events. Therefore
P(6 from the red die AND 6 from the green die) = (1/6)*(1/6) = 1/36.
Answer: 1/36
