Respuesta :
Answer : The expression for reaction quotient will be :
(1) [tex]Q_c=\frac{[SO_2][HF]^4}{[SF_4]}[/tex]
(2) [tex]Q_c=\frac{[O_2]^2[Xe]}{[XeF_2]}[/tex]
Explanation :
Reaction quotient [tex](Q_c)[/tex] : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.
(1) The given balanced chemical reaction is,
[tex]SF_4(g)+2H_2O(l)\rightarrow SO_2(g)+4HF(g)[/tex]
In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted. So, the expression for reaction quotient will be :
[tex]Q_c=\frac{[SO_2][HF]^4}{[SF_4]}[/tex]
(2) The given balanced chemical reaction is,
[tex]2MoO_2(s)+XeF_2(g)\rightarrow 2MoF(l)+Xe(g)+2O_2(g)[/tex
In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted. So, the expression for reaction quotient will be :
[tex]Q_c=\frac{[O_2]^2[Xe]}{[XeF_2]}[/tex]
1. The reaction quotient ([tex]Q_c[/tex]) for the chemical reaction of gaseous sulfur tetrafluoride with liquid water to produce gaseous sulfur dioxide and hydrogen fluoride gas is:
[tex]Q_c = \frac{[S0_{2}_{(g)}]\;[HF_{(g)}]^4}{[SF_{4}_{(g)}]}[/tex]
2. The reaction quotient ([tex]Q_c[/tex]) for the chemical reaction of solid molybdenum (VI) oxide with gaseous xenon difluoride to form liquid molybdenum (VI) fluoride, xenon gas, and oxygen gas is:
[tex]Q_c = \frac{[Xe_{(g)}]^6\;[O_{2}_{(g)}]^3}{[XeF_{2}_{(g)}]^6}[/tex]
Reaction quotient ([tex]Q_c[/tex]) can be defined as a measure of the relative amounts of products and reactants that are present in a balanced chemical reaction with well-defined stoichiometry, at a specific period of time.
Mathematically, reaction quotient ([tex]Q_c[/tex]) is given by the formula:
[tex]Q_c = \frac{[C]^c[D]^d}{[A]^a[B]^b}[/tex]
Where:
- C and D are products.
- A and B are reactants.
- c is moles of product C.
- d is moles of product D.
- a is moles of reactant A.
- b is moles of reactant B.
Note: Reaction quotient ([tex]Q_c[/tex]) only shows products and reactants in the gaseous or aqueous states. Both solid and liquid chemical components are omitted because they have an activity of one.
1. The chemical reaction of gaseous sulfur tetrafluoride with liquid water to produce gaseous sulfur dioxide and hydrogen fluoride gas is given by the balanced chemical equation:
[tex]SF_{4}_{(g)}+2H_2O_{(l)}--->S0_{2}_{(g)} + 4HF_{(g)}[/tex]
Reaction quotient, [tex]Q_c = \frac{[S0_{2}_{(g)}]\;[HF_{(g)}]^4}{[SF_{4}_{(g)}]}[/tex]
2. The chemical reaction of solid molybdenum (VI) oxide with gaseous xenon difluoride to form liquid molybdenum (VI) fluoride, xenon gas, and oxygen gas is given by the balanced chemical equation:
[tex]2MoO_3_{(s)} + 6XeF_{2}_{(g)} ---> 2MoF_{6}_{(l)} + 6Xe_{(g)} + 3O_{2}_{(g)}[/tex]
Reaction quotient, [tex]Q_c = \frac{[Xe_{(g)}]^6\;[O_{2}_{(g)}]^3}{[XeF_{2}_{(g)}]^6}[/tex]
Read more: https://brainly.com/question/13750908
