Step-by-step explanation:
It is given that,
Initial speed of the car, u = 40 m/s
Final speed of the car, v = 25 m/s
Time taken, t = 3.5 s
(a) We need to find the magnitude and direction of the car’s acceleration as it slows down. It can be calculated using formula as :
[tex]a=\dfrac{v-u}{t}[/tex]
[tex]a=\dfrac{25-40}{3.5}[/tex]
[tex]a=-4.28\ m/s^2[/tex]
The acceleration is in the opposite direction of motion i.e. west.
(b) Let s is the distance the car travel in the 3.5-s time period. It can be calculated using the third equation of motion as
[tex]s=\dfrac{v^2-u^2}{2a}[/tex]
[tex]s=\dfrac{25^2-40^2}{2\times (-4.28)}[/tex]
s = 113.9 meters
Hence, this is the required solution.
