Melody invested $7,500 into two accounts. One account paid 5% interest and the other paid 7.5% interest. She earned 6% interest on the total investment. How much money did she put in each account?

Respuesta :

Answer:

The amount put in the account that paid 5% was $4,500 and the amount put in the account that paid 7.5% was $3,000

Step-by-step explanation:

Let

x -----> the amount put in the account that paid 5%

$7,500-x -----> the amount put in the account that paid 7.5%

in this problem we have

[tex]6\%=6/100=0.06[/tex]

[tex]5\%=5/100=0.05[/tex]

[tex]7.5\%=7.5/100=0.075[/tex]

so

[tex]7,500(0.06)=x(0.05)+(7,500-x)0.075[/tex]

[tex]450=0.05x+562.5-0.075x[/tex]

[tex]0.075x-0.050x=562.5-450[/tex]

[tex]0.025x=112.5[/tex]

[tex]x=\$4,500[/tex]

[tex]\$7,500-x=\$3,000[/tex]

therefore

The amount put in the account that paid 5% was $4,500 and the amount put in the account that paid 7.5% was $3,000

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