Answer: The change in enthalpy will be -13.
Explanation:-
Endothermic reactions are those in which heat is absorbed by the system and exothermic reactions are those in which heat is released by the system.
[tex]\Delta H[/tex] for Endothermic reaction is positive and [tex]\Delta H[/tex] for Exothermic reaction is negative.
[tex]2A+2B\rightarrow 6C+26kJ[/tex]
[tex]2A+2B\rightarrow 6C[/tex] [tex]\DeltaH=-26kJ[/tex]
When 1 mole of A combining with 1 mole of B to produce 3 moles of C
Thus as the stoichiometry has got half of the original , enthalpy of the reaction will also get half.
Thus for reaction :
[tex]A+B\rightarrow 3C+\frac{26}{2}kJ[/tex]
[tex]A+B\rightarrow 3C[/tex] [tex]\DeltaH=-13kJ[/tex]
Thus the change in enthalpy will be -13.
The second thermochemical equation as shown above and the enthalpy in kJ is +13 KJ.
The first thermochemical reaction equation for the reaction is written as follows; 2A + 2B ----> 6C ΔH = +26 kJ
The second thermochemical reaction equation for the reaction is written as follows; A + B -----> 3C = ΔH = +13 KJ
We can clearly see that the second reaction is obtained from the first reaction by dividing through each term by 2. If this is done, we obtain the second thermochemical equation as shown above and the enthalpy in kJ is +13 KJ.
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