If the nerve cell connecting the spinal cord to your feet is 1.4 m long, and the nerve impulse speed is 25 m/s, how many seconds does it take for the nerve signal to travel this distance?

Respuesta :

Answer:

Time taken by the nerve signal for travelling this distance [tex]= 0.056[/tex] seconds

Explanation:

Given,

The length of nerve cell connecting the spinal cord to the feet [tex]= 1.4 m [/tex]

Speed of nerve impulse [tex]25\frac{m}{s}[/tex]

Time taken for  the nerve signal to travel this distance is equal to the total " length of nerve cell connecting the spinal cord to the feet" divided by "speed of nerve impulse"

Substituting the given values in above equation, we get -

[tex]\frac{1.4}{25}[/tex]

[tex]= 0.056[/tex] seconds.

Thus , time taken by the nerve signal for travelling this distance [tex]= 0.056[/tex] seconds

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