After landing, a jetliner on a straight runway taxis to a stop at an average velocity of If the plane takes 7.00 s to come to rest, what are the plane’s initial velocity and acceleration?

Respuesta :

Answer:

Plane's initial speed: 14[tex]\frac{m}{s}[/tex]

Plane's acceleration: -1 [tex]\frac{m}{s^{2} }[/tex]

Explanation:

average velocity =[tex]\frac{V_{0} +V_f }{2}[/tex]

V0=?

Vf= 0 m/s (rest)

t=7 s

Isolating V0

V0=2a-Vf = 2*(7) - 0= 14[tex]\frac{m}{s}[/tex]

Otherwise;

[tex]a= \frac{V_f-V_0}{t} = \frac{0\frac{m}{s}-7\frac{m}{s}  }{7s} = -1 \frac{m}{s^2}[/tex]

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