Find the horizontal and vertical components of the vector with the given length and direction, and write the vector in terms of the vectors i and j. |????| = 11, θ = 225°

Respuesta :

Answer:

horizontal component =-7.77  vertical component =-7.77

vector = -7.77 i -7.77 j

Step-by-step explanation:

We have given magnitude let V = 11

And angle [tex]\Theta =225[/tex]

For finding we take cos component of the magnitude

Horizontal component [tex]V_X=Vcos\Theta =11cos225^{\circ}=-7.77i[/tex]

For finding the vertical we take sine component of the magnitude

Vertical component[tex]V_Y=Vsin\Theta =11sin225^{\circ}=-7.77j[/tex]

So vector will be -7.77 i -7.77 j

Answer:

Step-by-step explanation:

Length of vector, R = 11 units

angle, θ = 225°

The horizontal component of the vector is given by

Rx = R Cosθ = 11 Cos 225° = - 7.778

The vertical component of the vector is given by

Rx = R Sinθ = 11 Sin 225° = - 7.778

The vector representation of the vector is given by

[tex]\overrightarrow{R}=R_{x}\widehat{i}+R_{y}\widehat{j}[/tex]

[tex]\overrightarrow{R}=-7.778\widehat{i}-7.778\widehat{j}[/tex]

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