Answer:
Force exerted, F = 1.5 N
Explanation:
It is given that, a boxer punches a sheet of paper in midair and brings it from rest up to a speed of 30 m/s in 0.060 s.
i.e. u = 0
v = 30 m/s
Time taken, t = 0.06 s
Mass of the paper, m = 0.003 kg
We need to find the force the boxer exert on it. The force can be calculated using second law of motion as :
[tex]F=m\times a[/tex]
[tex]F=m\times (\dfrac{v-u}{t})[/tex]
[tex]F=0.003\times (\dfrac{30}{0.06})[/tex]
F = 1.5 N
So, the force the boxer exert on the paper is 1.5 N. Hence, this is the required solution.
