The temperature inside a certain industrial machine at time t seconds after startup, for 0 < t < 10, is given by h(t) = 42t + 1 – 4t + 2 degrees Celsius. How many seconds after startup is the temperature inside the machine equal to 128 degrees Celsius?

Respuesta :

Answer:

[tex]t= \frac{125}{38} s[/tex]

Step-by-step explanation:

We are given the temperature inside the machine from startup until 10 seconds later, the formula is:

[tex]h(t)= 42 \cdot t +1 - 4\cdot t +2  (degrees \, C)[/tex]

We want to know at what time t the temperature inside the machine will be equal to 128 °C.

So we set:

[tex]h(t)=128[/tex]

[tex]42\cdot t+1-4\cdot t+2=128[/tex]

Now, we rearrange the equation to keep terms with t on the left hand side and terms without t on the right hand side

[tex]42\cdot t-4\cdot t=128-1-2[/tex]

and we simplify:

[tex](42-4)\cdot t= 128-2-1= 125[/tex]

[tex]38 \cdot t = 125[/tex]

now it's easy to solve for t:

[tex]t=\frac{125}{38}[/tex]

And thus we arrive to the solution.

Q&A Education