Answer:
28 m/s^2
Explanation:
distance, s = 14 m
time, t = 2 - 1 = 1 s
initial velocity, u = 0 m/s
Let a be the acceleration.
Use third equation of motion
[tex]s = ut + \frac{1}{2}at^{2}[/tex]
[tex]14 = 0 + \frac{1}{2}a\times 1^{2}[/tex]
a = 28 m/s^2
Thus, the acceleration is 28 m/s^2.
