Answer: One canister contains 1.03 Kg of fuel,
Explanation:
The density is defined as the relation between the mass and the volume [tex]p=\frac{m}{v}[/tex]
First of all you need to have the same units for volume and density, so:
For the volume,
[tex]1.45 L * \frac{1.10*10^{-3}m^{3} }{1 L} = 1.45 *10^{-3} m^{3}[/tex]
For the density,
[tex]p = 0.710\frac{g}{cm^{3} } *\frac{1cm^{3} }{1*10^{-6}m^{3} }*\frac{1 Kg}{1*10^{3}g } = 710\frac{Kg}{m^{3} }[/tex]
From the density equation we have [tex]m=p*v[/tex], so:
[tex]710\frac{Kg}{m^{3} } *1.45*10^{-3} m^{3} = 1.03Kg[/tex]
