Respuesta :
Answer:
Maximum amount of ammonia that can be formed is 6.32 g
Explanation:
The balanced equation is:
N2 + 3H2\rightarrow 2NH3
[tex]Moles\ N2 = \frac{5.21g}{28g/mol} =0.186\\\\Moles H2 = \frac{5.21g}{2g/mol} =2.61[/tex]
N2 is the limiting reactant
Based on the reaction stoichiometry:
1 mole N2 produced 2 moles NH3
therefore, 0.186 mol N2 will yield: 2(0.186) = 0.372 moles NH3
Molar mass NH3 = 17 g/mol
[tex]Maximum\ Mass\ NH3 = 0.372 mols*17g/mol=6.32g[/tex]
