Respuesta :
Answer:1148.6 N
Step-by-step explanation:
Given
mass of block =5 kg
Inclination angle [tex]\theta =37^{\circ}[/tex]
constant acceleration(a)[tex]=5.6m/s^2[/tex]
[tex]\mu [/tex] be the coefficient of kinetic friction =0.05
we know friction force[tex]=\mu N[/tex]
forces acting on block is [tex]mgsin\theta [/tex]down the inclined plane
friction force acting parallel to surface opposing [tex]mgsin\theta [/tex]
Therefore
[tex]mgsin\theta - \mu N=ma[/tex]
[tex]\frac{m\left ( gsin\theta +a\right )}{\mu }=N[/tex]
[tex]N=\frac{5\left ( 9.81\times 0.6+5.6\right )}{0.05}[/tex]
N=1148.6 N
