Answer:
[tex]YZ=38\ units[/tex]
Step-by-step explanation:
we know that
If Y is between X and Z
then
[tex]XZ=XY+YZ[/tex]
substitute the given values and solve for a
([tex]5a+22)=(3a-4)+(6a+2)\\(5a+22)=(9a-2)\\9a-5a=22+2\\4a=24\\a=6[/tex]
Find the length of YZ
[tex]YZ=6a+2[/tex]
substitute the value of a
[tex]YZ=6(6)+2=38\ units[/tex]
