Respuesta :
Answer:
Coefficient of [tex]H^{+}(aq)[/tex] is more than 4
Explanation:
Oxidation: [tex]Sn^{2+}(aq)\rightarrow Sn^{4+}(aq)[/tex]
- Balance charge: [tex]Sn^{2+}(aq)-2e^{-}\rightarrow Sn^{4+}(aq)[/tex]......(1)
Reduction: [tex]Cr_{2}O_{7}^{2-}(aq)\rightarrow Cr^{3+}(aq)[/tex]
- Balance Cr: [tex]Cr_{2}O_{7}^{2-}(aq)\rightarrow 2Cr^{3+}(aq)[/tex]
- Balance O and H in acidic medium: [tex]Cr_{2}O_{7}^{2-}(aq)+14H^{+}(aq)\rightarrow 2Cr^{3+}(aq)+7H_{2}O(l)[/tex]
- Balance charge: [tex]Cr_{2}O_{7}^{2-}(aq)+14H^{+}(aq)+6e^{-}\rightarrow 2Cr^{3+}(aq)+7H_{2}O(l)[/tex].......(2)
[tex][3\times Equation-(1)]+Equation(2)[/tex] gives balanced equation:
[tex]3Sn^{2+}(aq)+Cr_{2}O_{7}^{2-}(aq)+14H^{+}(aq)\rightarrow 3Sn^{4+}(aq)+2Cr^{3+}(aq)+7H_{2}O(l)[/tex]
So coefficient of [tex]H^{+}(aq)[/tex] is more than 4
