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Step-by-step explanation:

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Answer:

The domain of the given function is:

              [tex]x>-8\ \text{and}\ x\neq 0[/tex]

Step-by-step explanation:

Domain of a function--

The domain of a function is the set of all the x-values i.e. the value of the independent variable for which a function is well defined.

We have a function f(x) and g(x) as follows:

[tex]f(x)=\dfrac{1}{x}\\\\g(x)=\sqrt{x+8}[/tex]

Hence,

[tex](\dfrac{f}{g})(x)=\dfrac{1}{x\sqrt{x+8}}[/tex]

Now, we know that this function is well defined when the denominator quantity is defined and also when the denominator quantity is non-zero.

This means that:

          [tex]x\neq 0[/tex]

and

[tex]\sqrt{x+8}\neq 0[/tex]

i.e.

[tex]x\neq -8[/tex]

Now we know that the square root function is defined when the radicand is greater than zero.

i.e.

[tex]x+8\geq 0\\\\x\geq -8[/tex]

But [tex]x\neq -8[/tex]

This means that:

[tex]x>-8[/tex]

Hence, the domain is:

                       [tex]x>-8\ \text{and}\ x\neq 0[/tex]

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