Answer:
233.12 deg
Explanation:
[tex]F_{1}[/tex] = Force acting on the object in right direction = 6.0 N
[tex]F_{2}[/tex] = Force acting on the object in upward direction = 8.0 N [tex]\theta[/tex] = Angle made by the resultant force relative to right direction
From the diagram , Angle made by the resultant force relative to right direction is given as
[tex]\theta = tan^{-1}\left ( \frac{F_{2}}{F_{1}} \right )[/tex]
[tex]\theta = tan^{-1}\left ( \frac{8}{6} \right )[/tex]
[tex]\theta = 53.12[/tex] deg
[tex]\phi[/tex] = Angle of equilibrium force relative to the right direction
From the diagram, Angle of equilibrium force relative to the right direction is given as
[tex]\phi = \theta + 180[/tex]
[tex]\phi = 53.12 + 180[/tex]
[tex]\phi = 233.12[/tex] deg
