Answer:
Explanation:
diameter at 23 degree celcius is 4.511 mm
GIVEN DATA:
diameter of hole = 4.500 mm
T_1 = 23.0 Degree celcius
T_2 = - 78.0 Degree celcius
expansion coeffcient of Al = 2.4*10^{-5} (degree celcius)^{-1}
diameter at 23 degree celcius is given as
[tex]d = d_o (1+ \alpha \delta T)[/tex]
[tex] = 4.5 (1+2.4*10^{-5} *(23-(-78)))[/tex]
= 4.511 mm
diameter of rivet after change in temperature is given as
[tex]d= d_o + \Delta d[/tex]
[tex]= d_o(1+ \alpha \delta T)[/tex]
[tex] = 0.4500 *(1+2.4*10^{-5} *(23-(-78)))[/tex]
= 0.4511 cm
