Answer:
[tex]C(t)=(0.5)e^{-\frac{ln 2}{1.5}t}[/tex]
Step-by-step explanation:
Given :
After alcohol is fully absorbed into the body, it is metabolized with a half-life of about 1.5 hours.
Your blood alcohol concentration (BAC) is 0.5 mg/mL.
To Find : Find an exponential decay model for your BAC t hours after midnight.
Solution:
General form of decay model : [tex]C(t)=C_oe^{-kt}[/tex]
Where [tex]C_0[/tex] is the initial BAC
C(t) is the BAC after t hours
k is the decay constant
Now we are given that After alcohol is fully absorbed into the body, it is metabolized with a half-life of about 1.5 hours.
Formula : [tex]t_{\frac{1}{2}} =\frac{ln 2}{k}[/tex]
[tex]1.5=\frac{ln 2}{k}[/tex]
[tex]k=\frac{ln 2}{1.5}[/tex]
[tex]k=\frac{ln 2}{1.5}[/tex]
Your blood alcohol concentration (BAC) is 0.5 mg/mL..
So, [tex]C_0=0.5[/tex]
So, Â [tex]C(t)=(0.5)e^{-\frac{ln 2}{1.5}t}[/tex]
Hence an exponential decay model for your BAC t hours after midnight is [tex]C(t)=(0.5)e^{-\frac{ln 2}{1.5}t}[/tex]