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In addition to their remarkable top speeds of almost 60 mph, cheetahs have impressive cornering abilities. In one study, the maximum centripetal acceleration of a cheetah was measured to be 17 m/s2.What minimum value of the coefficient of static friction between the ground and the cheetah's feet is necessary to provide this acceleration?

Respuesta :

Answer:

coefficient of static friction is 1.7329

Explanation:

given data

velocity = 60 mph

acceleration  = 17 m/s²

to find out

coefficient of static friction

solution

we will apply here centripetal force equation

that is

m×v²/r  =  µ × m × g      ..................1

here v²/r is centripetal acceleration and m is mass and  µ  is coefficient static friction so

µ = a / g

µ = 17 / 9.81

µ  = 1.7329

so coefficient of static friction is 1.7329

okpalawalter8

We have that for the Question it can be said that The minimum value of the coefficient of static friction between the ground and the cheetah's feet  necessary to provide this acceleration is

[tex]a_c=1.73[/tex]

From the question we are told

  • In addition to their remarkable top speeds of almost 60 mph, cheetahs have impressive cornering abilities. In one study, the maximum centripetal acceleration of a cheetah was measured to be 17 m/s2.

  • What minimum value of the coefficient of static friction between the ground and the cheetah's feet is necessary to provide this acceleration?

Generally the equation for the centripetal force  is mathematically given as

[tex]m\frac{v^2}{r}=\mu mg\\\\Where\\\\a_c=\frac{V^2}{t}\\\\a_c=\frac{17}{9.81}\\\\[/tex]

[tex]a_c=1.73[/tex]

Therefore

The minimum value of the coefficient of static friction between the ground and the cheetah's feet  necessary to provide this acceleration is

[tex]a_c=1.73[/tex]

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https://brainly.com/question/23379286

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