Answer:
The mass of water produced is 59.22 g
Explanation:
This is the balanced equation of methane combustion:
CH₄(g) + 2O₂(g) → CO₂(g) +2H₂O(g)
This equation is balanced because we have the same amount of each element at each side of the equation:
Left side:
CH₄= 1C and 4H
2O₂ = (2x2)O = 4O
Total: 1C, 4H, and 4O
Right side:
CO₂ = 1C and 2O
2H₂O = (2x2)H + (2x1)O = 4H + 2O
Total: 1C, 4H, and 4O
Once it is balanced, we know from the equation that 1 mol of methane (1 CH₄) produces two mols of water ( 2 H₂O) when it reacts with oxygen. The mass of a mol of methane is:
Molar mass CH₄ in grams = mass of the carbon atom + mass of the four H atoms.
Molar mass CH₄ = 12 + 4 = 16 g
The same procedure with water:
Molar mass H₂O in grams = mass of the 2 H atoms + mass of the O atom
Molar mass H₂O in grams = 2 + 16 = 18 g
Hence 16 g (1 mol) CH4 will produce 36 (18 x 2)g H2O.
Therefore:
16 g CH4 ⇒ 36 g H20
26.32 g CH4 ⇒ x= 26.32 * 36 / 16 = 59.22 g.
Have a nice day!
