Answer:
position as a function of time is y = 0.05 × cos(9.9)t
Explanation:
given data
mass = 5 kg
length = 10 cm = 0.1 m
displaced = 5 cm
to find out
position as a function of time
solution
we will apply here equilibrium that is
mass × g = k × length
put here value and find k
k = [tex]\frac{5*9.8}{.01}[/tex]
k = 490 N/m
and ω is
ω = [tex]\sqrt{\frac{k}{m} }[/tex]
ω = [tex]\sqrt{\frac{490}{5} }[/tex]
ω = 9.9
so here position w.r.t time is
y = 0.05 × cosωt
y = 0.05 × cos(9.9)t
so position as a function of time is y = 0.05 × cos(9.9)t
