Answer:
1.984 m/s^2
Explanation:
initial velocity of air craft, u = 0 m/s
final speed of the aircraft, v = 120 km/h
Convert the speed into m/s from km/h
So, v = 120 km/h = 33.33 m/s
distance, s = 280 m
Let a be the acceleration of the aircraft.
Use third equation of motion
[tex]v^{2}=u^{2}+2\times a\times s[/tex]
[tex]33.33^{2}=0^{2}+2\times a\times 280[/tex]
a = 1.984 m/s^2
Thus, the acceleration of the aircraft is 1.984 m/s^2.
