Answer:
The solution to the system of linear equations is the set of vectors of the form
[tex](t, \frac{2t}{11}, \frac{28t}{11}, \frac{-9t}{11}), \,\,t\in \mathbb{R}[/tex]
Step-by-step explanation:
There are several computer algebra systems (CAS) that you can use. In Mathematica you can enter the input shown below to get the solution:
```
Solve[{8y+z+3w==0, x-y+w==0, 23y-z+2w==0}, {x,y,z,w}]
```
What you obtain as an output is a list as follows:
[tex]\{\{y\to \frac{2x}{11}, z\to \frac{28x}{11},w\to \frac{-9x}{11}\}\}[/tex]
For more details see the image below.
