Answer:
From certain assumptions that the walking speed is 2 m/s, and the stop time is 0.1 s the acceleration would be -20 m/s
Explanation:
Using the average acceleration formula:
[tex]a=\frac{\Delta v}{\Delta t}[/tex] where [tex]\Delta v[/tex] and [tex]\Delta t[/tex] are the changes in the speed and time respectively.
We have by assuming that the walking speed is 2 m/s and the stop time is 0.1s which is equal to the change in time during the stopping.
[tex]\Delta v=v_f-v_i=0-2 m/s=-2 m/s[/tex], where [tex]v_i,v_f[/tex] are the initial speed and final speed respectively, and [tex]\Delta t=0.1 s[/tex]
Plugging the previous in the average acceleration formula we get
[tex]a=\frac{-2}{0.1}=-20\, m/s[/tex] where the minus sign indicates an acceleration in the opposite direction of the motion (or in other word opposite to the speed's direction).
