A rock is suspended by a light string. When the rock is in air, the tension in the string is 42.2 N . When the rock is totally immersed in water, the tension is 30.6 N . When the rock is totally immersed in an unknown liquid, the tension is 21.0 N . What is the density of the unknown liquid?

Respuesta :

Answer:

1.83 g/cm^3

Explanation:

Weight of rock in air = 42.2 N

Weight f rock in water = 30.6 N

Weight of rock in unknown liquid =  21.0 N

The relative density of the unknown liquid is given by the following formula

[tex]relative density of unknown liquid = \frac{weight in air - weight in liquid}{weight in air - weight in water}[/tex]

[tex]relative density of unknown liquid = \frac{42.2-21.0}{42.2-30.6}[/tex]

= 1.83

So, the density of unknown liquid is 1.83 g/cm^3.

Thus, the density of the unknown liquid is 1.83 g/cm^3.

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