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The amplitudes of the displacement and acceleration of an unbalanced motor were measured to be 0.15 mm and 0.6*g, respectively. Determine the speed of the motor . Use g=9.81 m/s^2 .

Respuesta :

Answer:

The speed of shaft is 1891.62 RPM.

Explanation:

given that

Amplitude A= 0.15 mm

Acceleration = 0.6 g

So

we can say that acceleration= 0.6 x 9.81

[tex]acceleration,a=5.88\ \frac{m}{s^2}[/tex]

We know that

[tex]a=\omega ^2A[/tex]

So now by putting the values

[tex]a=\omega ^2A[/tex]

[tex]5.88=\omega ^2 \0.15\times 10^{-3}[/tex]

[tex]\omega =198.09\ \frac{rad}{s}[/tex]

We know that

  ω= 2πN/60

198.0=2πN/60

N=1891.62 RPM

So the speed of shaft is 1891.62 RPM.

                                               

       

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