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In a carnival game you roll a ball up a ramp and into a basket. During one attempt, you roll the ball so that it has a velocity of 6.0 m/s i^ at the bottom of the ramp and 2.0 m/s i^ at the top (where i^ points up the ramp). If it takes 1.5 s for the ball to roll from the bottom to the top of the ramp, the ball’s average acceleration is ______ m/s2 i^.

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ShreedharJagtap

Explanation:

The formula for average acceleration is

[tex]a = \frac{v - u}{t} [/tex]

Now, v (final speed) = 2 m/s

and u (initial speed) = 6 m/s

Substituting in the formula,

[tex]a = \frac{2 - 6}{1.5} \\ a = \frac{ - 4}{1.5} \\ [/tex]

[tex]a = - 2.667 \: { ms}^{ - 2} [/tex]

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