Respuesta :
Answer: The empirical formula of X is [tex]C_{5}H_4O_2[/tex].
Explanation:
If percentage are given then we are taking total mass is 100 grams.
So, the mass of each element is equal to the percentage given.
Mass of C = 62.4 g
Mass of H = 4.19 g
Mass of O = 33.2 g
Step 1 : convert given masses into moles.
Moles of C=[tex]\frac{\text{ given mass of Na}}{\text{ molar mass of Na}}= \frac{62.4g}{12g/mole}=5.2moles[/tex]
Moles of H=[tex]\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{4.19g}{1g/mole}=4.19moles[/tex]
Moles of O = [tex]\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{33.2g}{16g/mole}=2.1moles[/tex]
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For C =[tex]\frac{5.2}{2.1}=2.5[/tex]
For H =[tex]\frac{4.19}{2.1}=2[/tex]
For O =[tex]\frac{2.1}{2.1}=1[/tex]
The ratio of C: H: O = 2.5 : 2 : 1
Converting it into simple whole number ratios by multiplying by 2:
Hence the empirical formula of X is [tex]C_{5}H_4O_2[/tex].
