Respuesta :
Answer:
a)[tex]1.45\times 10^{-2}\ \rm C[/tex]
b)[tex]1.76\times10^{-3}\ \rm C[/tex]
Explanation:
Given:
Charge on particle(1) =[tex]69.9\ \mu C[/tex]
Charge on particle(3) =[tex]22.1\ \mu C[/tex]
Angle made by particle 1 with the x axis
[tex]\tan \theta=\dfrac{4.32}{4.32}\\\theta =45^\circ[/tex]
Angle made by particle 3 with the x axis
[tex]\tan \theta=\dfrac{4.32}{36.1}\\\theta =6.82^\circ[/tex]
a) If the acceleration particle 3 is along the positive x axis then then it means the net force on the charge along y axis is zero so
[tex]\dfrac{k\times 69.9}{r_1^2}\times \sin45^\circ=\dfrac{k\times Q}{r_2^2}\times \sin6.28^\circ\\\dfrac{k\times 69.9}{37.32}\times \sin45^\circ=\dfrac{k\times Q}{1321.8}\times \sin6.28^\circ\\Q=1.45\times10^{-2}\ \rm C[/tex]
b) If the acceleration particle 3 is along the positive y axis then then it means the net force on the charge along x axis is zero so
[tex]\dfrac{k\times 69.9}{r_1^2}\times \cos45^\circ=\dfrac{k\times Q}{r_2^2}\times \cos6.28^\circ\\\dfrac{k\times 69.9}{37.32}\times \cos45^\circ=\dfrac{k\times Q}{1321.8}\times \cos6.28^\circ\\\\Q=1.76\times10^{-3}\ \rm C[/tex]
