Respuesta :
Answer: 64.1 ml of concentrated [tex]HCl[/tex] is taken and (250-64.4)= 185.6 ml f water is added to make 250.00 mL of 3.00 M HCl .
Explanation:
Given : 36 g of [tex]HCl[/tex] is dissolved in 100 g of solution.
Density of solution = 1.18 g/ml
Thus volume of solution = [tex]\frac{mass}{density}=\frac{100}{1.18}=84.7ml[/tex]
[tex]Molarity=\frac{n\times 1000}{V_s}[/tex]
where,
n= moles of solute
[tex]Moles=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{36g}{36.5g/mol}=0.99moles[/tex]
[tex]V_s[/tex] = volume of solution
[tex]Molarity=\frac{0.99\times 1000}{84.7}=11.7M[/tex]
According to the dilution law,
[tex]M_1V_1=M_2V_2[/tex]
where,
[tex]M_1[/tex] = molarity of stock [tex]HCl[/tex] solution = 11.7M
[tex]V_1[/tex] = volume of stock [tex]HCl[/tex] solution = V ml
[tex]M_2[/tex] = molarity of diluted [tex]HCl[/tex] solution = 3.00 M
[tex]V_2[/tex] = volume of diluted [tex]HCl[/tex] solution = 250.0 ml
[tex]11.7M\times V=3.00\times 250.0[/tex]
[tex]V=64.1ml[/tex]
Thus 64.1 ml of stock [tex]HCl[/tex] is taken and (250-64.4)= 185.6 ml of water is added to make 250.00 mL of 3.00 M HCl .
