The final velocity or the muzzle velocity of the bullet at an average rate of 6.20×10⁵ m/s² for 8.10×10⁻⁴ s is 502.2 m\sec.
Given to us
Acceleration of the bullet, a = [tex]6.20\times 10^5 \rm\ m/s^2[/tex]
Time taken by the bullet, t = [tex]8.10\times 10^{-4}\rm\ s[/tex]
We know according to the first equation of motion the acceleration can be written as,
[tex]a=\dfrac{v-u}{t}[/tex]
As the bullet at the beginning was rest, therefore, it was not shot, the initial velocity, u =0.
Substitute the values in the equation of motion,
[tex]6.20 \times 10^5=\dfrac{v-(0)}{8.10\times 10^{-4}}[/tex]
[tex]v = 502.2\rm\ m/sec[/tex]
Hence, the final velocity or the muzzle velocity of the bullet at an average rate of 6.20×10⁵ m/s² for 8.10×10⁻⁴ s is 502.2 m\sec.
Learn more about the Equation of motion:
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