Respuesta :
Answer:
11505 bacteria
Step-by-step explanation:
Given :
The bacteria in a certain culture triples every 7.7 hours. The culture has 6,500 bacteria at the start .
As per the exponential growth , we have [tex]A=P_0\left ( R \right )^{\frac{T}{P}}[/tex]
Here ,
[tex]P_0[/tex] is starting number of bacteria
R is rate at which number of bacteria increases
T is time elapsed
P is one period of rate
[tex]P_0 = 6500\\R=3\\T=4\\P=7.7[/tex]
On putting these values in formula [tex]A=P_0\left ( R \right )^{\frac{T}{P}}[/tex] , we get
[tex]A=P_0\left ( R \right )^{\frac{T}{P}}\\=6500\left ( 3 \right )^{\frac{4}{7.7}}\\ \approx 6500\left ( 3 \right )^{0.5195}\\=6500\times 1.77\\=11505[/tex]
So, the culture will contain 11505 bacteria after four hours .
