Answer: The molality of the CsCl solution is 3.2 m.
Explanation:
Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.
[tex]Molality=\frac{n\times 1000}{W_s}[/tex]
where,
n = moles of solute
moles of solute =[tex]\frac{\text {given mass}}{\text {molar mass}}=\frac{31.9g}{168.36g/mol}=0.19moles[/tex]
Now put all the given values in the formula of molarity, we get
[tex]W_s[/tex] = weight of solvent (water) in g = 60.0 g
Molality =[tex]\frac{0.19\times 1000}{60}=3.2mol/kg[/tex]
Thus molality of the CsCl solution is 3.2 m.
