Answer:
Final speed of the train, v = 168.61 m/s
Explanation:
It is given that,
Acceleration of the train, [tex]a=0.71\ m/s^2[/tex]
Time taken, t = 3.85 min = 231 s
Initial velocity of the train, u = 4.6 m/s
We need to find the final velocity (v) of the train. It can be calculated using first equation of motion as :
[tex]v=u+at[/tex]
[tex]v=4.6+0.71\times 231[/tex]
v = 168.61 m/s
So, the final velocity of the train is 168.61 m/s. Hence, this is the required solution.
